COMEDK · Physics · 19. Current Electricity
The maximum current that can be measured by a galvanometer of resistance \(40 \Omega\) is \(10 \mathrm{~mA}\). It is converted into a voltmeter that can read upto \(50 \mathrm{~V}\). The resistance to be connected in series with the galvanometer (in ohm) is
- A 5040
- B 4960
- C 2010
- D 4050
Answer & Solution
Correct Answer
(B) 4960
Step-by-step Solution
Detailed explanation
Given, resistance of the galvanometer, \(G=40 \Omega\) Current in the galvanometer, \[ l_{g}=10 \mathrm{~m} \mathrm{~A}=10 \times 10^{3} \mathrm{~A} \] Maximum reading of voltmeter, \(V=50 \mathrm{~V}\) The galvanometer can be converted into voltmeter by connecting a shunt…
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