ExamBro
ExamBro
COMEDK · Physics · 19. Current Electricity

The maximum current that can be measured by a galvanometer of resistance \(40 \Omega\) is \(10 \mathrm{~mA}\). It is converted into a voltmeter that can read upto \(50 \mathrm{~V}\). The resistance to be connected in series with the galvanometer (in ohm) is

  1. A 5040
  2. B 4960
  3. C 2010
  4. D 4050
Verified Solution

Answer & Solution

Correct Answer

(B) 4960

Step-by-step Solution

Detailed explanation

Given, resistance of the galvanometer, \(G=40 \Omega\) Current in the galvanometer, \[ l_{g}=10 \mathrm{~m} \mathrm{~A}=10 \times 10^{3} \mathrm{~A} \] Maximum reading of voltmeter, \(V=50 \mathrm{~V}\) The galvanometer can be converted into voltmeter by connecting a shunt…