COMEDK · Physics · 9. Gravitation
The maximum and minimum distances of a comet from the sun are \(1.4 \times 10^{12} \mathrm{~m}\) and \(7 \times 10^{10} \mathrm{~m}\). If its velocity nearest to the sun is \(6 \times 10^{14} \mathrm{~ms}^{-1}\), what is its velocity in the farthest position?
(Assume the comet to be spherical)
- A \(3 \times \mathrm{10}^{-18} \quad\)
- B \(2 \times \mathrm{10}^{-18} \quad\)
- C \(\mathrm{10}^{-18} \quad\)
- D \(4 \times \mathrm{10}^{-18} \quad\)
Answer & Solution
Correct Answer
(A) \(3 \times \mathrm{10}^{-18} \quad\)
Step-by-step Solution
Detailed explanation
The given situation is shown below \(a_{\max }=1.4 \times 10^{12} \mathrm{~m}\) \(a_{\min }=7 \times 10^{10} \mathrm{~m}\) The velocity of the comet is maximum, when it is nearest to the sun and minimum when it is farthest from the sun.…
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