COMEDK · Physics · 8. Rotational Motion
The masses of \(200 \mathrm{~g}\) and \(300 \mathrm{~g}\) are attached to the \(20 \mathrm{~cm}\) and \(70 \mathrm{~cm}\) marks of a light meter rod, respectively. The moment of inertia of the system about an axis passing through \(50 \mathrm{~cm}\) mark is
- A \(0.15 \mathrm{~kg} \mathrm{~m}^{2}\)
- B \(0.036 \mathrm{~kg} \mathrm{~m}^{2}\)
- C \(0.3 \mathrm{~kg} \mathrm{~m}^{2}\)
- D Zero
Answer & Solution
Correct Answer
(B) \(0.036 \mathrm{~kg} \mathrm{~m}^{2}\)
Step-by-step Solution
Detailed explanation
Given, \(1 m_{1}=200 \mathrm{~g}=0.2 \mathrm{~kg}\) \[ \begin{gathered} m_{2}=300 \mathrm{~g}=0.3 \mathrm{~kg} \\ l_{1}=50-20=30 \mathrm{~cm} \\ \Rightarrow \quad l_{1}=0.3 \mathrm{~m} \\ l_{2}=70-50=20 \mathrm{~cm}=0.8 \mathrm{~m} \end{gathered} \] \(\therefore\) Moment of…
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