COMEDK · Physics · 17. Electrostatics
The magnitude and direction of the electric field in a particular region is \((10 \boldsymbol{i}+4 \boldsymbol{j}+2 \boldsymbol{k}) \times 10^4 \mathrm{NC}^{-1}\). What s the electric flux through an area \((3 \boldsymbol{i}-\boldsymbol{k}) 10^{-2} \mathrm{~m}^2\)
- A \(1.4 \times 10^3 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- B \(2.8 \times 10^3 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- C \(2.8 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- D \(2.8 \times 10^2 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
Answer & Solution
Correct Answer
(B) \(2.8 \times 10^3 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
Step-by-step Solution
Detailed explanation
The electric flux \(\Phi_E\) through a surface is given by the dot product of the electric field vector \(\vec{E}\) and the area vector \(\vec{A}\). Given \(\vec{E} = (10 \hat{i} + 4 \hat{j} + 2 \hat{k}) \times 10^4 \text{ NC}^{-1}\) and…
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