COMEDK · Physics · 21. Magnetic Effects of Current
The magnetic field at the centre of a circular current carrying conductor of radius \(r\) is \(B_{c}\). The magnetic field on its axis at a distance \(r\) from the centre is \(B_{a}\). The value of \(B_{c}: B_{a}\) will be
- A \(1: \sqrt{2}\)
- B \(1: 2 \sqrt{2}\)
- C \(2 \sqrt{2}: 1\)
- D \(\sqrt{2}: 1\)
Answer & Solution
Correct Answer
(C) \(2 \sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
Magnetic field at the centre of circular carrying conductor, \[ B_{c}=\frac{\mu_{0} I}{2 r} \] Magnetic on the axis at a distance \(x\) from the centre is given as \[ B_{\text {axis }}=\frac{\mu_{0} I r^{2}}{2\left(r^{2}+x^{2}\right)^{3 / 2}} \] Here, \(x=r\)…
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