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COMEDK · Physics · 23. Alternating Current

The instantaneous values of alternating current and voltages in a circuit are \(I=\dfrac{3}{\sqrt{2}} \sin (200 \pi t)\) ampere and \(\mathrm{V}=\dfrac{3}{\sqrt{2}} \sin \left(200 \pi t+\dfrac{\pi}{6}\right)\) volt. What is the average power consumed in the circuit in watt?

  1. A \(\dfrac{6 \sqrt{3}}{8}\)
  2. B \(\dfrac{9 \sqrt{3}}{8}\)
  3. C \(\dfrac{\sqrt{3}}{8}\)
  4. D \(\dfrac{8 \sqrt{2}}{9}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\dfrac{9 \sqrt{3}}{8}\)

Step-by-step Solution

Detailed explanation

The given expressions for current and voltage are \(I = \dfrac{3}{\sqrt{2}} \sin(200 \pi t)\) and \(V = \dfrac{3}{\sqrt{2}} \sin(200 \pi t + \dfrac{\pi}{6})\). The peak current is \(I_0 = \dfrac{3}{\sqrt{2}}\) A and the peak voltage is \(V_0 = \dfrac{3}{\sqrt{2}}\) V. The root…