COMEDK · Physics · 23. Alternating Current
The instantaneous values of alternating current and voltages in a circuit are \(I=\dfrac{3}{\sqrt{2}} \sin (200 \pi t)\) ampere and \(\mathrm{V}=\dfrac{3}{\sqrt{2}} \sin \left(200 \pi t+\dfrac{\pi}{6}\right)\) volt. What is the average power consumed in the circuit in watt?
- A \(\dfrac{6 \sqrt{3}}{8}\)
- B \(\dfrac{9 \sqrt{3}}{8}\)
- C \(\dfrac{\sqrt{3}}{8}\)
- D \(\dfrac{8 \sqrt{2}}{9}\)
Answer & Solution
Correct Answer
(B) \(\dfrac{9 \sqrt{3}}{8}\)
Step-by-step Solution
Detailed explanation
The given expressions for current and voltage are \(I = \dfrac{3}{\sqrt{2}} \sin(200 \pi t)\) and \(V = \dfrac{3}{\sqrt{2}} \sin(200 \pi t + \dfrac{\pi}{6})\). The peak current is \(I_0 = \dfrac{3}{\sqrt{2}}\) A and the peak voltage is \(V_0 = \dfrac{3}{\sqrt{2}}\) V. The root…
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