COMEDK · Physics · 9. Gravitation
The height vertically above the earth's surface at which the acceleration due to gravity becomes \(1 \%\) of its value at the surface is
- A \(8 R\)
- B \(9 R\)
- C \(10 R\)
- D \(20 R\)
Answer & Solution
Correct Answer
(B) \(9 R\)
Step-by-step Solution
Detailed explanation
Acceleration due to gravity at a height \(h\) from the earth's surface, \(g^{\prime}=\frac{G M}{(R+h)^2}\) Given, \(\quad g^{\prime}=1 \%\) of \(g=\frac{g}{100}\)…
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