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COMEDK · Physics · 9. Gravitation

The height at which the acceleration due to gravity becomes \(\dfrac{g}{16}\) (where, \(g=\) acceleration due to gravity on the surface of the earth) in terms of \(R\) is, if \(R\) is the radius of earth.

  1. A \(2 R\)
  2. B \(3 R\)
  3. C \(\sqrt{2} R\)
  4. D \(\sqrt{3} R\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3 R\)

Step-by-step Solution

Detailed explanation

The acceleration due to gravity at a height \(h\) above the surface of the earth is given by the formula \(g_h = g \left( \dfrac{R}{R + h} \right)^2\), where \(g\) is the acceleration due to gravity at the surface and \(R\) is the radius of the earth. Given that…