COMEDK · Physics · 28. Atomic Physics
The first emission of hydrogen atomic spectrum in Lyman series appears at a wavelength of
- A \(\frac{3 R}{4} \mathrm{~cm}^{-1}\)
- B \(\frac{4}{3 R} \mathrm{~cm}\)
- C \(\frac{7 R}{144} \mathrm{~cm}^{-1}\)
- D \(\frac{400}{9 R} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(B) \(\frac{4}{3 R} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { We know that, } \frac{1}{\lambda}=R\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right) \\ & \Rightarrow \quad \frac{1}{\lambda}=R\left(\frac{1}{1_1^2}-\frac{1}{2^2}\right)=\frac{3 R}{4} \Rightarrow \lambda=\frac{4}{3 R} \mathrm{~cm}\end{aligned}\)
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