COMEDK · Physics · 9. Gravitation
The escape velocity is \(11.2 \mathrm{~km} / \mathrm{s}\). If a body is to be projected in a direction making an angle \(60^{\circ}\) to the vertical, then the escape velocity is
- A \(11.2 \times \sqrt{2} \mathrm{~km} / \mathrm{s}\)
- B \(\frac{11.2}{\sqrt{2}} \mathrm{~km} / \mathrm{s}\)
- C \(11.2 \sqrt{3} \mathrm{~km} / \mathrm{s}\)
- D \(11.2 \mathrm{~km} / \mathrm{s}\)
Answer & Solution
Correct Answer
(D) \(11.2 \mathrm{~km} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
Escape velocity does not depend on the angle of projection, hence escape velocity remains same.
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