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COMEDK · Physics · 9. Gravitation

The escape velocity is \(11.2 \mathrm{~km} / \mathrm{s}\). If a body is to be projected in a direction making an angle \(60^{\circ}\) to the vertical, then the escape velocity is

  1. A \(11.2 \times \sqrt{2} \mathrm{~km} / \mathrm{s}\)
  2. B \(\frac{11.2}{\sqrt{2}} \mathrm{~km} / \mathrm{s}\)
  3. C \(11.2 \sqrt{3} \mathrm{~km} / \mathrm{s}\)
  4. D \(11.2 \mathrm{~km} / \mathrm{s}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(11.2 \mathrm{~km} / \mathrm{s}\)

Step-by-step Solution

Detailed explanation

Escape velocity does not depend on the angle of projection, hence escape velocity remains same.