COMEDK · Physics · 3. Motion In One Dimension
The displacement \(x\) (in \(\mathrm{m}\)) of a particle of mass \(\mathrm{m}\) (in \(\mathrm{kg}\) ) moving in one dimension under the action of a force, is related to time \(t\) (in \(\mathrm{s}\)) by \(t=\sqrt{x}+3\). The displacement of the particle when its velocity is zero, will be
- A \(4 \mathrm{~m}\)
- B \(0\)
- C \(6 \mathrm{~m}\)
- D \(2 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
Given, \(t=\sqrt{x}+3\) \(\Rightarrow \quad \sqrt{x}=t-3\) or \(\quad x=(t-3)^{2}\) Velocity, \(v=\frac{d x}{d t}=\frac{d}{d t}(t-3)^{2}=2(t-3)\) When velocity of particle is zero, then…
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