COMEDK · Physics · 28. Atomic Physics
The difference in energy levels of an electron at two excited levels is \(13.75 \mathrm{~eV}\). If it makes a transition from the higher energy level to the lower energy level then what will be the wave length of the emitted radiation?
[given \(h=6.6 \times 10^{-34} \mathrm{~m}^2 \mathrm{~kg} \mathrm{~s}^{-1} ; c=3 \times 10^8 \mathrm{~ms}^{-1} ; 1 \mathrm{~eV}=1.6 \times 10^{-19} \mathrm{~J}\)]
- A \(9^0 \mathrm{~A}\)
- B \(900^{\circ} \mathrm{A}\)
- C \(9000 \mathrm{~nm}\)
- D \(900 \mathrm{~nm}\)
Answer & Solution
Correct Answer
(B) \(900^{\circ} \mathrm{A}\)
Step-by-step Solution
Detailed explanation
The energy difference between the two levels is given by \(\Delta E = 13.75 \text{ eV}\). Converting this energy into Joules: \(\Delta E = 13.75 \times 1.6 \times 10^{-19} \text{ J} = 22 \times 10^{-19} \text{ J}\). The relationship between energy and wavelength is…
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