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COMEDK · Physics · 28. Atomic Physics

The difference in energy levels of an electron at two excited levels is \(13.75 \mathrm{~eV}\). If it makes a transition from the higher energy level to the lower energy level then what will be the wave length of the emitted radiation?
[given \(h=6.6 \times 10^{-34} \mathrm{~m}^2 \mathrm{~kg} \mathrm{~s}^{-1} ; c=3 \times 10^8 \mathrm{~ms}^{-1} ; 1 \mathrm{~eV}=1.6 \times 10^{-19} \mathrm{~J}\)]

  1. A \(9^0 \mathrm{~A}\)
  2. B \(900^{\circ} \mathrm{A}\)
  3. C \(9000 \mathrm{~nm}\)
  4. D \(900 \mathrm{~nm}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(900^{\circ} \mathrm{A}\)

Step-by-step Solution

Detailed explanation

The energy difference between the two levels is given by \(\Delta E = 13.75 \text{ eV}\). Converting this energy into Joules: \(\Delta E = 13.75 \times 1.6 \times 10^{-19} \text{ J} = 22 \times 10^{-19} \text{ J}\). The relationship between energy and wavelength is…
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