COMEDK · Physics · 19. Current Electricity
The current sensitivity of a galvanometer having 20 divisions is \(10 \mu \mathrm{A} /\) div. If the resistance of the galvanometer is \(100 \Omega\) then the value of the resistance to be used to convert this galvanometer in to an voltmeter to read up to \(1 \mathrm{~V}\) is :
- A \(4 \times 10^{-6} \Omega\) in series with the galvanometer.
- B \(4900 \Omega\) in parallel with the galvanometer.
- C \(4 \times 10^{-3} \Omega\) in series with the galvanometer.
- D \(4900 \Omega\) in series with the galvanometer.
Answer & Solution
Correct Answer
(D) \(4900 \Omega\) in series with the galvanometer.
Step-by-step Solution
Detailed explanation
The full scale deflection current \(I_g\) of the galvanometer is calculated by multiplying the number of divisions by the current sensitivity per division.…
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