COMEDK · Physics · 18. Capacitance
The capacitance of a parallel plate capacitor is \(400 \mathrm{~pF}\). It is connected to an ac source of \(100 \mathrm{~V}\) having an angular frequency \(100 \mathrm{~rad~s}^{-1}\). If the rms value of the current is \(4 \mu \mathrm{A}\), the displacement current is:
- A 4 \(\mu\)A
- B \(4 \times 10^{-2} \mu \mathrm{A}\)
- C 4 A
- D 0.4 \(\mu\)A
Answer & Solution
Correct Answer
(A) 4 \(\mu\)A
Step-by-step Solution
Detailed explanation
The displacement current \(I_d\) in a parallel plate capacitor is defined as the current flowing through the circuit, which is equal to the conduction current \(I_c\) in the connecting wires. The relationship between the conduction current and the displacement current is given…
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