COMEDK · Physics · 29. Nuclear Physics
The atomic mass of an element \({}_{10}X^{20}\) is 19.98170 amu. The binding energy per nucleon of that element is:
[given mass of neutron = 1.00867 amu and mass of proton = 1.00783 amu and 1amu = 931 MeV]
- A \(85.33\) MeV / nucleon
- B \(17.66\) MeV / nucleon
- C \(170.66\) MeV / nucleon
- D \(8.533\) MeV / nucleon
Answer & Solution
Correct Answer
(D) \(8.533\) MeV / nucleon
Step-by-step Solution
Detailed explanation
Number of protons, \(Z = 10\) Number of neutrons, \(A - Z = 20 - 10 = 10\) Total mass of nucleons \(= 10 m_p + 10 m_n\) Total mass of nucleons \(= 10(1.00783) + 10(1.00867) = 10.0783 + 10.0867 = 20.1650\) amu Mass defect,…
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