COMEDK · Physics · 4. Motion In Two Dimensions
The angle of projection with the horizontal in terms of maximum height attained and horizontal range is given by
- A \(\tan ^{-1}\left(\dfrac{2 H}{3 R}\right)\)
- B \(\tan ^{-1}\left(\dfrac{4 R}{3 H}\right)\)
- C \(\tan ^{-1}\left(\dfrac{4 H}{R}\right)\)
- D \(\tan ^{-1}\left(\dfrac{R}{H}\right)\)
Answer & Solution
Correct Answer
(C) \(\tan ^{-1}\left(\dfrac{4 H}{R}\right)\)
Step-by-step Solution
Detailed explanation
The maximum height \(H\) attained by a projectile is given by \(H = \dfrac{u^2 \sin^2 \theta}{2g}\). The horizontal range \(R\) of the projectile is given by \(R = \dfrac{u^2 \sin(2\theta)}{g} = \dfrac{2u^2 \sin \theta \cos \theta}{g}\). Dividing the expression for \(H\) by the…
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