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COMEDK · Physics · 25. Ray Optics

Suppose refractive index \(\mu\) is given as \(\mu=A+\frac{B}{\lambda^{2}}\), where \(A\) and \(B\) are constants and \(\lambda\) is wavelength, then dimensions of \(B\) are same as that of

  1. A wavelength
  2. B volume
  3. C pressure
  4. D area
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Answer & Solution

Correct Answer

(D) area

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Detailed explanation

Refractive index, \(\mu=A+\frac{B}{\lambda^{2}}\) According to principle of homogeneity, Dimension of \(\frac{B}{\lambda^{2}}=\) Dimension of \(\mu\)…