COMEDK · Physics · 25. Ray Optics
Suppose refractive index \(\mu\) is given as \(\mu=A+\frac{B}{\lambda^{2}}\), where \(A\) and \(B\) are constants and \(\lambda\) is wavelength, then dimensions of \(B\) are same as that of
- A wavelength
- B volume
- C pressure
- D area
Answer & Solution
Correct Answer
(D) area
Step-by-step Solution
Detailed explanation
Refractive index, \(\mu=A+\frac{B}{\lambda^{2}}\) According to principle of homogeneity, Dimension of \(\frac{B}{\lambda^{2}}=\) Dimension of \(\mu\)…
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