COMEDK · Physics · 12. Thermal Properties of Matter
Rods \(A\) and \(B\) have their lengths in the ratio \(1: 2\). Their thermal conductivities are \(K_1\) and \(K_2\) respectively. The temperatures at the ends of each rod are \(T_1\) and \(T_2\). If the rate of flow of heat through the rods is equal, the ratio of area of cross section of \(A\) to that of \(B\) is
- A \(\dfrac{K_2}{K_1}\)
- B \(\dfrac{2 K_2}{K_1}\)
- C \(\dfrac{K_2}{4 K_1}\)
- D \(\dfrac{K_2}{2 K_1}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{K_2}{2 K_1}\)
Step-by-step Solution
Detailed explanation
The rate of heat flow \(H\) through a rod is given by the formula \(H = \dfrac{KA(T_1 - T_2)}{L}\), where \(K\) is the thermal conductivity, \(A\) is the area of cross-section, \(L\) is the length, and \((T_1 - T_2)\) is the temperature difference across the ends. Given that the…
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