COMEDK · Physics · 23. Alternating Current
Output of an \(A C\) source is \(V=100 \sin 100 \pi t \cos\) \(100 \pi t\). Which of these are correct?
- A Peak voltage of source is 100 V
- B Peak voltage of source is \(50 \sqrt{2} \mathrm{~V}\)
- C Peak voltage of source is 50 V
- D Frequency of the source is 50 Hz
Answer & Solution
Correct Answer
(C) Peak voltage of source is 50 V
Step-by-step Solution
Detailed explanation
The given output voltage can be written as \(\begin{aligned} V=100 \sin & 100 \pi t \cos 100 \pi t \\ & =50 \times 2 \sin 100 \pi t \cos 100 \pi t \\ & =50 \sin 2(100 \pi t) \quad[\because 2 \sin A \cos A=\sin 2 A] \\ & =50 \sin 200 \pi t \end{aligned}\) \(\therefore\) Peak…
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