COMEDK · Physics · 4. Motion In Two Dimensions
One end of the string of length \(l\) is connected to a particle of mass \(m\) and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed \(v\), the net force on the particle (directed towards centre) will be ( \(T\) represents the tension in the string)
- A \(T\)
- B \(T+\frac{m v^2}{l}\)
- C \(T-\frac{m v^2}{l}\)
- D zero
Answer & Solution
Correct Answer
(A) \(T\)
Step-by-step Solution
Detailed explanation
Consider the string of length \(l\) connected to a particle as shown in the figure Speed of the particle is \(v\). As, the particle is in uniform circular motion, the net force on the particle must be equal to centripetal force which is provided by the tension \((T)\).…
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