COMEDK · Physics · 27. Dual Nature of Matter
Let \(K_1\) be the maximum kinetic energy of photoelectrons emitted by light of wavelength \(\lambda_1\) and \(K_2\) corresponding to wavelength \(\lambda_2\). If \(\lambda_1=2 \lambda_2\), then
- A \(K_1=2 K_2\)
- B \(K_1 < K_2 / 2\)
- C \(2 K_1=K_2\)
- D \(K_1>2 K_2\)
Answer & Solution
Correct Answer
(B) \(K_1 < K_2 / 2\)
Step-by-step Solution
Detailed explanation
According to Einstein's photoelectric equation, the maximum kinetic energy \(K\) of emitted photoelectrons is given by \(K = \dfrac{hc}{\lambda} - \phi\), where \(\phi\) is the work function of the metal. For wavelength \(\lambda_1\), \(K_1 = \dfrac{hc}{\lambda_1} - \phi\). For…
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