COMEDK · Physics · 27. Dual Nature of Matter
\(\mathrm{K}_1\) and \(\mathrm{K}_2\) are maximum kinetic energies of photoelectrons emitted when lights of wavelength \(\lambda_1\) and \(\lambda_2\) respectively are incident on a metallic surface. If \(\lambda_1=3 \lambda_2\), then
- A \(\mathrm{K}_1=\left(\dfrac{1}{3}\right) \mathrm{K}_2\)
- B \(\mathrm{K}_1>3 \mathrm{~K}_2\)
- C \(\mathrm{K}_1<\left(\dfrac{1}{3}\right) \mathrm{K}_2\)
- D \(\mathrm{K}_1>\left(\dfrac{1}{3}\right) \mathrm{K}_2\)
Answer & Solution
Correct Answer
(C) \(\mathrm{K}_1<\left(\dfrac{1}{3}\right) \mathrm{K}_2\)
Step-by-step Solution
Detailed explanation
According to Einstein's photoelectric equation, the maximum kinetic energy \(K\) of emitted photoelectrons is given by \(K = \dfrac{hc}{\lambda} - \Phi\), where \(\Phi\) is the work function of the metal. For wavelengths \(\lambda_1\) and \(\lambda_2\), we have:…
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