COMEDK · Physics · 26. Wave Optics
Incident light of wavelength \(\lambda=800 \mathrm{~nm}\) produces a diffraction pattern on a screen \(1.5 \mathrm{~m}\) away when it passes through a single slit of width \(0.5 \mathrm{~mm}\). The distance between the first dark fringes on either side of the central bright fringe is
- A 2.4 cm
- B 4.8 cm
- C 4.8 mm
- D 2.4 mm
Answer & Solution
Correct Answer
(C) 4.8 mm
Step-by-step Solution
Detailed explanation
The condition for the first dark fringe in a single slit diffraction pattern is given by \(a \sin \theta = n \lambda\), where \(a\) is the slit width, \(\lambda\) is the wavelength, and \(n = 1\) for the first dark fringe. Since \(\theta\) is very small,…
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