COMEDK · Physics · 26. Wave Optics
In Young's double slit interference experiment, using two coherent waves of different amplitudes, the intensities ratio between bright and dark fringes is 3 . Then, the value of the ratio of the amplitudes of the wave that arrive there is
- A \(\sqrt{3}: 1\)
- B \(\left(\dfrac{\sqrt{3}+1}{\sqrt{3}-1}\right)\)
- C \(1: \sqrt{3}\)
- D \(\left(\dfrac{\sqrt{3}-1}{\sqrt{3}+1}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\dfrac{\sqrt{3}+1}{\sqrt{3}-1}\right)\)
Step-by-step Solution
Detailed explanation
Let the amplitudes of the two coherent waves be \(A_1\) and \(A_2\). The intensity of a wave is proportional to the square of its amplitude, \(I \propto A^2\). The maximum intensity \(I_{max}\) at bright fringes is given by \(I_{max} = (A_1 + A_2)^2\) and the minimum intensity…
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