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COMEDK · Physics · 26. Wave Optics

In Young's double slit interference experiment, using two coherent waves of different amplitudes, the intensities ratio between bright and dark fringes is 3 . Then, the value of the ratio of the amplitudes of the wave that arrive there is

  1. A \(\left(\frac{\sqrt{3}+1}{\sqrt{3}-1}\right)\)
  2. B \(\left(\frac{\sqrt{3}-1}{\sqrt{3}+1}\right)\)
  3. C \(\sqrt{3}: 1\)
  4. D \(1: \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left(\frac{\sqrt{3}+1}{\sqrt{3}-1}\right)\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { Here, } \frac{I_{\text {bright }}}{I_{\text {dark }}}=\frac{I_{\max }}{I_{\min }}=3 (given) \\ & \Rightarrow \quad \frac{\left(a_1+a_2\right)^2}{\left(a_1-a_2\right)^2}=\frac{3}{1} \Rightarrow \frac{a_1+a_2}{a_1-a_2}=\sqrt{3} \\ & \Rightarrow \quad…