COMEDK · Physics · 26. Wave Optics
In Young's double slit experiment the ratio of phase difference between light waves reaching the third bright fringe and third dark fringe is
- A \(\dfrac{7}{6}\)
- B \(\dfrac{4}{3}\)
- C \(\dfrac{5}{2}\)
- D \(\dfrac{6}{5}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{6}{5}\)
Step-by-step Solution
Detailed explanation
In Young's double slit experiment, the path difference \(\Delta x\) for the \(n\)-th bright fringe is given by \(\Delta x = n\lambda\), where \(n = 0, 1, 2, \dots\). The phase difference \(\phi\) is related to the path difference by \(\phi = \dfrac{2\pi}{\lambda} \Delta x\). For…
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