ExamBro
ExamBro
COMEDK · Physics · 26. Wave Optics

In Young's double slit experiment, the fringe width is found to be \(0.4 \mathrm{~mm}\). If the whole apparatus is immersed in a liquid of refractive index \(\dfrac{4}{3}\) without changing geometrical arrangement, the new fringe width will be

  1. A 0.45 mm
  2. B 0.4 mm
  3. C 0.53 mm
  4. D 0.30 mm
Verified Solution

Answer & Solution

Correct Answer

(D) 0.30 mm

Step-by-step Solution

Detailed explanation

The fringe width \(\beta\) in Young's double slit experiment is given by the formula \(\beta = \dfrac{\lambda D}{d}\), where \(\lambda\) is the wavelength of light, \(D\) is the distance between the slits and the screen, and \(d\) is the distance between the two slits. When the…