COMEDK · Physics · 18. Capacitance
In the figure, first the capacitors are fully charged by closing the key \(\mathrm{K}\). Then after opening the Key a dielectric material with dielectric constant 2 is filled in the space between the plates of both the capacitor. At this state the ratio of the Charge on the capacitor \(C_1\) to that of \(C_2\) is:
- A 2 : 1
- B 1 : 1
- C 1 : 2
- D 3 : 2
Answer & Solution
Correct Answer
(A) 2 : 1
Step-by-step Solution
Detailed explanation
When key K is closed, both \(C_1\) and \(C_2\) (\(= 1\ \mu F\) each) are connected to the 12V battery. Initial charge on both: \(Q_1 = Q_2 = 1\ \mu F \times 12\ V = 12\ \mu C\) When key K is opened, \(C_2\) gets isolated — its charge stays constant at \(12\ \mu C\). \(C_1\)…
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