COMEDK · Physics · 7. Center of Mass Momentum and Collision
In the diagram shown below, \(m_1\) and \(m_2\) are the masses of two particles and \(x_1\) and \(x_2\) are their respective distances from the origin \(O\).

The centre of mass of the system is
- A \(\dfrac{m_1 m_2+x_1 x_2}{m_1+m_2}\)
- B \(\dfrac{m_1 x_1+m_2 x_2}{m_1+m_2}\)
- C \(\dfrac{m_1+m_2}{2}\)
- D \(\dfrac{m_1 x_2+m_2 x_2}{m_1+m_2}\)
Answer & Solution
Correct Answer
(B) \(\dfrac{m_1 x_1+m_2 x_2}{m_1+m_2}\)
Step-by-step Solution
Detailed explanation
The position of the centre of mass \(X_{cm}\) for a system of particles with masses \(m_1, m_2, ..., m_n\) at positions \(x_1, x_2, ..., x_n\) along a line is given by the formula: \(X_{cm} = \dfrac{\sum m_i x_i}{\sum m_i}\) For the given system with two particles of masses…
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