COMEDK · Physics · 30. Semiconductors
In the circuit given, the reverse breakdown voltage of the Zener diode is 4.8 V. The current through the Zener and the power dissipation in Zener is:
- A \(12.4\ \text{mA};\ 97.52\ \text{mW}\)
- B \(2.88\ \text{mA};\ 13.82\ \text{mW}\)
- C \(22.4\ \text{mA};\ 107.52\ \text{mW}\)
- D \(28.8\ \text{mA};\ 138.24\ \text{mW}\)
Answer & Solution
Correct Answer
(C) \(22.4\ \text{mA};\ 107.52\ \text{mW}\)
Step-by-step Solution
Detailed explanation
Given: Input voltage, \(V = 12\ \text{V}\) Zener voltage, \(V_z = 4.8\ \text{V}\) Series resistance, \(R_s = 250\ \Omega\) Load resistance, \(R_L = 750\ \Omega\) First, we check if the Zener diode is in the breakdown region. The voltage across the load without the Zener diode…
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