COMEDK · Physics · 26. Wave Optics
In an interference experiment, intensity ratio at the bright to dark fringe is \(9: 1\). Amplitudes of interfering waves are in the ratio
- A \(3: 1\)
- B \(9: 1\)
- C \(2: 1\)
- D \(4: 1\)
Answer & Solution
Correct Answer
(C) \(2: 1\)
Step-by-step Solution
Detailed explanation
Given, \(\frac{I_{\max }}{I_{\min }}=\frac{9}{1}\) As we know,…
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