COMEDK · Physics · 13. Thermodynamics
In an adiabatic process with the ratio of two specific heat, \(\gamma=\dfrac{3}{2}\), pressure is increased by \(\dfrac{2}{3} \%\), then decrease in the volume will be
- A \(\dfrac{4}{9} \%\)
- B \(\dfrac{2}{3} \%\)
- C \(4 \%\)
- D \(\dfrac{9}{4} \%\)
Answer & Solution
Correct Answer
(A) \(\dfrac{4}{9} \%\)
Step-by-step Solution
Detailed explanation
For an adiabatic process, the relation between pressure \(P\) and volume \(V\) is given by \(PV^{\gamma} = \text{constant}\). Taking the natural logarithm on both sides, we get \(\ln P + \gamma \ln V = \text{constant}\). Differentiating both sides, we obtain…
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