COMEDK · Physics · 26. Wave Optics
In a Young's double slit experiment, the slits are separated by 0.5 mm. Fringes are obtained on a screen which is placed at distance 1 m away from the slits. When the screen is moved 7 cm farther away, the fringe width changes by 63 \(\mu\)m. The wavelength of light used in the experiment will be:
- A \(4.5 \times 10^{-7}\ m\)
- B \(0.5 \times 10^{-9}\ m\)
- C \(4.5 \times 10^{-6}\ m\)
- D \(0.5 \times 10^{-7}\ m\)
Answer & Solution
Correct Answer
(A) \(4.5 \times 10^{-7}\ m\)
Step-by-step Solution
Detailed explanation
The fringe width in a Young's double slit experiment is given by \(\beta = \dfrac{\lambda D}{d}\) When the screen is moved by a distance \(\Delta D\), the change in fringe width is \(\Delta \beta = \dfrac{\lambda \Delta D}{d}\) Rearranging the formula to solve for the wavelength…
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