COMEDK · Physics · 23. Alternating Current
In a pure inductive circuit, a sinusoidal voltage \(V(t)=200 \sin 250 t\) is applied to a pure inductance of \(\mathrm{L}=0.02 \mathrm{H}\). The current through the coil is:
- A \(40 \cos \left[250 t+\dfrac{\pi}{2}\right]\)
- B \(40 \sin \left[250 t+\dfrac{\pi}{2}\right]\)
- C \(40 \cos \left[250 t-\dfrac{\pi}{2}\right]\)
- D \(40 \sin \left[250 t-\dfrac{\pi}{2}\right]\)
Answer & Solution
Correct Answer
(D) \(40 \sin \left[250 t-\dfrac{\pi}{2}\right]\)
Step-by-step Solution
Detailed explanation
The given voltage is \(V(t) = 200 \sin(250t)\). Comparing this with \(V(t) = V_m \sin(\omega t)\), we have \(V_m = 200 \text{ V}\) and \(\omega = 250 \text{ rad/s}\). The inductive reactance \(X_L\) is given by \(X_L = \omega L\). Substituting the given values,…
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