COMEDK · Physics · 30. Semiconductors
\(\text { In a p-n junction, the depletion layer of thickness } 1 \mu \mathrm{m} \text { has } 0.05 \mathrm{~V} \text { potential across it. The electric field in } N C^{-1} \text { is }\)
- A \(5 \times 10^{2}\)
- B \(5 \times 10^{-8}\)
- C \(5 \times 10^{5}\)
- D \(5 \times 10^{4}\)
Answer & Solution
Correct Answer
(D) \(5 \times 10^{4}\)
Step-by-step Solution
Detailed explanation
The electric field \(E\) in a depletion layer is related to the potential difference \(V\) and the thickness \(d\) by the formula \(E = \dfrac{V}{d}\). Given values are \(V = 0.05 \text{ V}\) and \(d = 1 \mu\text{m} = 1 \times 10^{-6} \text{ m}\). Substituting these values into…
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