COMEDK · Physics · 29. Nuclear Physics
In a nuclear reaction 2 deuteron nuclei combine to form a helium nucleus. The energy released in \(\mathrm{MeV}\) will be: (Given mass of deuteron \(=2.01355 \mathrm{~amu}\). and mass of helium nucleus \(=4.0028 \mathrm{~amu}\).
- A 0.0243 MeV
- B 24.3 MeV
- C 22.62 MeV
- D 2.262 MeV
Answer & Solution
Correct Answer
(C) 22.62 MeV
Step-by-step Solution
Detailed explanation
The nuclear reaction is given by: \(2_{1}^{2}H \rightarrow _{2}^{4}He + Q\). The mass of the reactants is \(2 \times 2.01355 \text{ amu} = 4.02710 \text{ amu}\). The mass of the product is \(4.0028 \text{ amu}\). The mass defect \(\Delta m\) is calculated as:…
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