COMEDK · Physics · 28. Atomic Physics
In a helium ion, if potential energy of electron in ground state is assumed to be zero, then its energy in first excited state is equal to
- A 13.6 eV
- B 27.2 eV
- C 54.4 eV
- D 95.2 eV
Answer & Solution
Correct Answer
(D) 95.2 eV
Step-by-step Solution
Detailed explanation
Potential energy of a \(\mathrm{He}^{+}\)ion in ground state is \(\begin{aligned} & U_1=2 E_1=2\left(-13.6 \frac{Z^2}{n^2}\right) \\ & \because \quad n=1 \text { and } Z=2 \\ & \Rightarrow \quad U_1=-108.8 \mathrm{eV} \end{aligned}\) But PE in ground state is given zero. So, we…
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