COMEDK · Physics · 29. Nuclear Physics
\(\text { If the nuclear radius of }{ }^{27} \mathrm{Al} \text { is } 3.6 \text { fermi, the nuclear radius of }{ }^{125} \mathrm{Fe} \text { is }\)
- A \(6 \times 10^{-12} \mathrm{~m}\)
- B \(6 \times 10^{-10} \mathrm{~m}\)
- C \(6 \times 10^{-13} \mathrm{~m}\)
- D \(6 \times 10^{-15} \mathrm{~m}\)
Answer & Solution
Correct Answer
(D) \(6 \times 10^{-15} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
The nuclear radius \(R\) is given by the formula \(R = R_0 A^{1/3}\), where \(R_0\) is a constant and \(A\) is the mass number of the nucleus. For \(^{27}\mathrm{Al}\), the mass number \(A_1 = 27\) and the radius \(R_1 = 3.6 \text{ fermi}\). Using the formula,…
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