COMEDK · Physics · 19. Current Electricity
If only \(2 \%\) of the main current is to be passed through a galvanometer of resistance \(G\), then the resistance of shunt should be
- A \(G / 50\)
- B \(G / 49\)
- C \(50 G\)
- D \(49 G\)
Answer & Solution
Correct Answer
(B) \(G / 49\)
Step-by-step Solution
Detailed explanation
For shunt resistance connected to galvanometer, current is given by \(I_{g}=\left(\frac{S}{S+G}\right) I\) \(\frac{2}{100} I=\left(\frac{S}{S+G}\right) I\) \(\begin{aligned} \Rightarrow & S+G &=50 S \\ \text { or } & S &=\frac{G}{49} \end{aligned}\)
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