COMEDK · Physics · 7. Center of Mass Momentum and Collision
If kinetic energy of a body is increased by \(300 \%\), then percentage change in momentum will be
- A \(100 \%\)
- B \(150 \%\)
- C \(265 \%\)
- D \(73.2 \%\)
Answer & Solution
Correct Answer
(A) \(100 \%\)
Step-by-step Solution
Detailed explanation
The kinetic energy \(K\) and momentum \(p\) of a body are related by the expression \(K = \dfrac{p^2}{2m}\), where \(m\) is the mass of the body. Let the initial kinetic energy be \(K_1\) and the initial momentum be \(p_1\). Then \(K_1 = \dfrac{p_1^2}{2m}\). The kinetic energy…
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