COMEDK · Physics · 9. Gravitation
If escape velocity on earth surface is \(11.1 \mathrm{kmh}^{-1}\), then find the escape velocity on moon surface. If mass of moon is \(\frac{1}{81}\) times of mass of earth and radius of moon is \(\frac{1}{4}\) times radius of earth.
- A \(2.46 \mathrm{kmh}^{-1}\)
- B \(3.46 \mathrm{kmh}^{-1}\)
- C \(4.4 \mathrm{kmh}^{-1}\)
- D None of these
Answer & Solution
Correct Answer
(A) \(2.46 \mathrm{kmh}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, Escape velocity on the surface of the earth is given by i.e. \(v_\rho=\sqrt{2 g R_e}\) Mass of the moon, \(M_m=\frac{M_e}{81}\) Radius of the moon, \(R_m=\frac{R_e}{4}\) \(\therefore\) Escape velocity on the surface of the moon…
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