COMEDK · Physics · 9. Gravitation
If escape velocity on earth surface is \(11.1 \mathrm{~kmh}^{-1}\), then find the escape velocity on moon surface. If mass of moon is \(\dfrac{1}{81}\) times of mass of earth and radius of moon is \(\dfrac{1}{4}\) times radius of earth.
- A \(4.4 \mathrm{~kmh}^{-1}\)
- B \(2.47 \mathrm{~kmh}^{-1}\)
- C None of these
- D \(3.46 \mathrm{~kmh}^{-1}\)
Answer & Solution
Correct Answer
(B) \(2.47 \mathrm{~kmh}^{-1}\)
Step-by-step Solution
Detailed explanation
The escape velocity \(v_e\) from the surface of a planet is given by the formula \(v_e = \sqrt{\dfrac{2GM}{R}}\), where \(M\) is the mass of the planet and \(R\) is its radius. Let \(M_e\) and \(R_e\) be the mass and radius of the Earth, and \(M_m\) and \(R_m\) be the mass and…
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