COMEDK · Physics · 26. Wave Optics
If \(E\) is the amplitude of the electric field of the waves starting from the slits in a double slit experiment and \(\theta\) is the phase difference between the waves reaching a point on the screen, the ratio of the amplitude of the resultant electric field at that point on the screen to the amplitude at one of the slits is
- A \(2 \cos \left(\dfrac{\theta}{2}\right)\)
- B \(2 \cos (\theta)\)
- C \(\cos \left(\dfrac{\theta}{2}\right)\)
- D \(\cos (\theta)\)
Answer & Solution
Correct Answer
(A) \(2 \cos \left(\dfrac{\theta}{2}\right)\)
Step-by-step Solution
Detailed explanation
Let the electric field of the waves from the two slits be \(E_1 = E \sin(\omega t)\) and \(E_2 = E \sin(\omega t + \theta)\), where \(E\) is the amplitude of each wave and \(\theta\) is the phase difference. The resultant electric field \(E_R\) is given by the superposition…
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