COMEDK · Physics · 18. Capacitance
If \(C\) be the capacitance and \(V\) be the electric potential, then the dimensional formula of \(\mathrm{CV}^2\) is
- A \(\left[\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^0\right]\)
- B \(\left[\mathrm{M}^0 \mathrm{LT}^{-2} \mathrm{~A}^0\right]\)
- C \(\left[\mathrm{ML}^{-3} \mathrm{TA}\right]\)
- D \(\left[\mathrm{MLT}^{-2} \mathrm{~A}^{-1}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\mathrm{ML}^2 \mathrm{~T}^{-2} \mathrm{~A}^0\right]\)
Step-by-step Solution
Detailed explanation
The energy \(U\) stored in a capacitor is given by the formula \(U = \dfrac{1}{2} CV^2\). Since \(U\) represents energy, its dimensional formula is the same as that of work or energy, which is \([ML^2T^{-2}]\). The factor \(\dfrac{1}{2}\) is a dimensionless constant and does not…
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