COMEDK · Physics · 1. Mathematics in Physics
If \(\alpha, \beta\) and \(\gamma\) are the angles between the vectors \(\overrightarrow{\mathrm{P}}, \overrightarrow{\mathrm{Q}}\), and \(\overrightarrow{\mathrm{R}}\) and \(\alpha=90^{\circ}\) as shown in figure. the product of \((\vec{Q} \times \vec{R}) \cdot \vec{Q}\) is equal to

- A Zero
- B \(R Q^2 \sin \theta \cos \theta\)
- C \(R Q^2 \sin\theta\)
- D \(R Q^2 \cos \theta\)
Answer & Solution
Correct Answer
(A) Zero
Step-by-step Solution
Detailed explanation
The expression given is \((\vec{Q} \times \vec{R}) \cdot \vec{Q}\). By the properties of the scalar triple product, the vector \((\vec{Q} \times \vec{R})\) is perpendicular to both \(\vec{Q}\) and \(\vec{R}\). Specifically, the cross product \(\vec{A} \times \vec{B}\) results in…
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