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COMEDK · Physics · 1. Mathematics in Physics

If \(\alpha, \beta\) and \(\gamma\) are the angles between the vectors \(\overrightarrow{\mathrm{P}}, \overrightarrow{\mathrm{Q}}\), and \(\overrightarrow{\mathrm{R}}\) and \(\alpha=90^{\circ}\) as shown in figure. the product of \((\vec{Q} \times \vec{R}) \cdot \vec{Q}\) is equal to

  1. A Zero
  2. B \(R Q^2 \sin \theta \cos \theta\)
  3. C \(R Q^2 \sin\theta\)
  4. D \(R Q^2 \cos \theta\)
Verified Solution

Answer & Solution

Correct Answer

(A) Zero

Step-by-step Solution

Detailed explanation

The expression given is \((\vec{Q} \times \vec{R}) \cdot \vec{Q}\). By the properties of the scalar triple product, the vector \((\vec{Q} \times \vec{R})\) is perpendicular to both \(\vec{Q}\) and \(\vec{R}\). Specifically, the cross product \(\vec{A} \times \vec{B}\) results in…
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