COMEDK · Physics · 28. Atomic Physics
If an electron in hydrogen atom jumps from an orbit of level \(n=3\) to an orbit at level \(n=2\), emitted radiation has a frequency of ( \(R=\) Rydberg's constant and \(c=\) velocity of light)
- A \(\dfrac{3 R c}{27}\)
- B \(\dfrac{R c}{25}\)
- C \(\dfrac{8 R c}{9}\)
- D \(\dfrac{5 R c}{36}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{5 R c}{36}\)
Step-by-step Solution
Detailed explanation
The frequency \(\nu\) of the radiation emitted when an electron jumps from an energy level \(n_2\) to \(n_1\) is given by the Rydberg formula: \(\nu = R c \left( \dfrac{1}{n_1^2} - \dfrac{1}{n_2^2} \right)\) Given \(n_1 = 2\) and \(n_2 = 3\), substitute these values into the…
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