COMEDK · Physics · 9. Gravitation
If \(\mathrm{A}\) is the areal velocity of a planet of mass \(\mathrm{M}\), then its angular momentum is
- A MA
- B \(\dfrac{\mathrm{MA}}{2}\)
- C \(\dfrac{\mathrm{MA}}{3}\)
- D \(2 \mathrm{MA}\)
Answer & Solution
Correct Answer
(D) \(2 \mathrm{MA}\)
Step-by-step Solution
Detailed explanation
The areal velocity of a planet is defined as the rate at which the area is swept by the radius vector, given by \(\dfrac{dA}{dt} = \dfrac{1}{2} r^2 \dfrac{d\theta}{dt}\). The angular momentum \(L\) of a planet of mass \(M\) moving in an orbit is given by…
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