COMEDK · Physics · 12. Thermal Properties of Matter
If a black body emits \(0.5 \mathrm{~J}\) of energy per second when it is at \(27^{\circ} \mathrm{C}\), then the amount of energy emitted by it when it is at \(627^{\circ} \mathrm{C}\) will be
- A \(40.5 \mathrm{~J}\)
- B \(162 \mathrm{~J}\)
- C \(13.5 \mathrm{~J}\)
- D \(135 \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(40.5 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Given, \(\begin{aligned} T_{1} &=27^{\circ} \mathrm{C}=(273+27) \mathrm{K}=300 \mathrm{~K} \\ T_{2} &=627^{\circ} \mathrm{C} \\ &=(627+273) \mathrm{K} \\ &=900 \mathrm{~K} \end{aligned}\) Energy emitted per second…
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