COMEDK · Physics · 17. Electrostatics
If 216 drops of the same size are charged at \(200 \mathrm{~V}\) each and they combine to form a bigger drop, the potential of the bigger drop will be
- A 8200 V
- B 7200 V
- C 1200 V
- D 2400 V
Answer & Solution
Correct Answer
(B) 7200 V
Step-by-step Solution
Detailed explanation
Let \(r\) be the radius of each small drop and \(q\) be the charge on each small drop. The potential of a small drop is given by \(V = \dfrac{kq}{r} = 200 \text{ V}\). When \(n = 216\) drops combine to form a bigger drop of radius \(R\) and charge \(Q\), the volume remains…
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