COMEDK · Physics · 20. Magnetic Properties of Matter
If \(\theta_1\) and \(\theta_2\) be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of \(\operatorname{dip} \theta\) is given by
- A \(\cot ^2 \theta=\cot ^2 \theta_1+\cot ^2 \theta_2\)
- B \(\cot ^2 \theta=\cot ^2 \theta_1-\cot ^2 \theta_2\)
- C \(\tan ^2 \theta=\tan ^2 \theta_1-\tan ^2 \theta_2\)
- D \(\tan ^2 \theta=\tan ^2 \theta_1+\tan ^2 \theta_2\)
Answer & Solution
Correct Answer
(A) \(\cot ^2 \theta=\cot ^2 \theta_1+\cot ^2 \theta_2\)
Step-by-step Solution
Detailed explanation
Let \(B\) be the total intensity of the Earth's magnetic field, \(B_H\) be the horizontal component, and \(B_V\) be the vertical component. The true angle of dip \(\theta\) is given by \(\tan \theta = \dfrac{B_V}{B_H}\). Consider two vertical planes at right angles to each…
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